AQA GCSE Chemistry contents

Unit 3 · Quantitative Chemistry

Using Moles in Equations [Higher Tier]

2 min read · part of the full Exam Guide

Amounts of substances in equations

  • The big numbers in a balanced equation are the mole ratio: Mg+2HCl→MgCl2+H2\text{Mg} + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{H}_2 means one mole of magnesium reacts with two moles of hydrochloric acid to make one mole of magnesium chloride and one mole of hydrogen
  • Reacting mass calculations always follow the same three steps:
    • Moles of the substance you know: mass ÷ Mr\div \, M_r
    • Ratio from the equation to get the moles of the substance you want
    • Mass of the substance you want: moles × Mr\times \, M_r
  • Worked example: mass of magnesium oxide made from 6 g of magnesium. 2Mg+O2→2MgO2\text{Mg} + \text{O}_2 \rightarrow 2\text{MgO}
    • Moles of Mg =624=0.25= \frac{6}{24} = 0.25 mol
    • Ratio Mg : MgO is 2 : 2, so 0.25 mol of MgO
    • Mass of MgO =0.25×40=10= 0.25 \times 40 = 10 g

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In the full topic

  • Amounts of substances in equations
  • Using moles to balance equations
  • Limiting reactants
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