AQA GCSE Chemistry contents

Unit 3 · Quantitative Chemistry

Percentage Yield & Atom Economy [Chemistry only]

2 min read · part of the full Exam Guide

Percentage yield

  • The yield is the amount of product actually obtained. It is usually less than the calculated maximum because:
    • The reaction is reversible and does not go to completion
    • Some product is lost when it is separated from the reaction mixture, for example on filter paper
    • Some reactants react in unexpected ways to make other products
% yield=mass of product actually mademaximum theoretical mass of product×100 \text{\% yield} = \frac{\text{mass of product actually made}}{\text{maximum theoretical mass of product}} \times 100
  • Worked example: a reaction should make 5.0 g of product and 3.8 g is collected. 3.85.0×100=76%\frac{3.8}{5.0} \times 100 = 76\%
  • (HT) The theoretical mass comes from a reacting mass calculation: moles of reactant, ratio, mass of product. Then the actual mass is compared with it
  • Worked example (HT): 10.0 g of calcium carbonate is heated and 4.2 g of calcium oxide is collected. CaCO3→CaO+CO2\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2
    • Moles of CaCO3=10.0100=0.100\text{CaCO}_3 = \frac{10.0}{100} = 0.100 mol, so 0.100 mol of CaO, theoretical mass 0.100×56=5.60.100 \times 56 = 5.6 g
    • Yield =4.25.6×100=75%= \frac{4.2}{5.6} \times 100 = 75\%

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  • Percentage yield
  • Atom economy
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